Find the line of symmetry for the parabola whose equation is y = 2x^2 - 4x + 1.

give the values of a, b, and c from the general form of the equation (2x + 1)(x - 2) = 0.

what is the line of symmetry for the graph of y = -3x^2 + 12x - 11?

what is the x-coordinate of the vertex of the parabola whose equation is y = 3x2 + 9x?

which of the following points lies on the graph of y = x^2 - 2x + 6?

the line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = -2. what is the value of "a"?

The line of symmetry of y = 2x^2 - 4x + 1.
the axis of symmetry of x= - b/2a,  so the line of symmetry is x= - 4/2x2= -1
x=-1

the values of a, b, and c from the general form of the equation (2x + 1)(x - 2) =(2x + 1)(x - 2) = 2x²-4x+x-2=2x²-3x-2=ax²+bx+c=0
by identifying, a =2, b=-3 and c=-2

the line of symmetry for the graph of y = -3x^2 + 12x - 11 is x= -b/2a, so
x= -12/2x-3=2, x=2

The x-coordinate of the vertex of the parabola whose equation is y = 3x2 + 9x, x=-b/2a=-9/6=-3/2

The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = -2. What is the value of "a"
y = ax2 - 4x + 3, x=-b/2a=-2, implies  -b=-2x2a, -(-4)=-2x2a, 4= -4a, a=-1

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for