What are the solutions to the following system of equations?
y = x2 + 3x − 7
3x − y = −2
(3, 11) and (−3, −7)
(11, 3) and (−3, −7)
(3, 11) and (−7, −3)
no real solutions

We will express second equation in first.

y = 3x + 2
after that we get:

3x + 2 = x^2 + 3x - 7
x^2 -9 = 0
x^2 = 9
x1 = 3
x2 = -3

y1 = 3*3+2 = 11
y2 = -3*3 + 2 = -7

we get pairs:
(3,11) and (-3,-7)

Answer is first option.

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