Arrange the parabolas with respect to the position of their vertices from left to right.

6,7,1,3,2,4,5

Step-by-step explanation:

             (1) f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4)  

             (2) x = k+3  

             (3) x = (k+1)/2 = (k/2)-(1/2)

             (4) x = 2(k+2) = 2k+4

             (5) x = k+7

             (6) x = k-3

             (7) x = k-2

For k = 0 the original positions will be:

            (1) -3/4

            (2) 3

            (3) -1/2

            (4) 4  

            (5) 7

            (6) -3

            (7) -2

So the order from left to right is 6,7,1,3,2,4,5.

step-by-step explanation:

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong