The tables below represent two different relations between the variables x and y. which relation is a function and which is not a function?

table 1:

x 0 -4 3 -2 9 3
y 5 8 7 8 5 -2

function or not function?

table 2:

x 2 -7 5 1 -6 3
y 5 8 -6 8 5 7

function or not function?

which ordered pair can be omitted from the non-function so that the relation is a function?

Table 1: Not a function.

Table 2: It is a function.

A relation is a function if each x value is mapped to a single y-value.

i.e. corresponding to each element there is a single image.

Table 1:  

x 0-43-293

y 58785-2

No, Table 1 is not a function.

Since there are two images of element '3'.

i.e. 3 is mapped to 7 and -2.

Table 2:

x 2-751-63

y 58-6857

Yes, this relation is a function.

Because corresponding to each x there is a single image.

If from Table 1 we delete the ordered pair either one of (3,7) or (3,-2) we will obtain the relation as a function.

98%

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.