15 points!
this image may be the result of
if m∠rqs is 75°, then m∠tpu is °.

fill in the blank #1 options:
a.) construction for copying line ab.
b.) construction of a line parallel to line ab through point p.
c.) construction of a line perpendicular to line ab and line pu.
d.) construction of a line perpendicular to line ab through point p.

fill in the blank #2 options:
a.) 15
b.) 75
c.) 105
d.) 150

make sure to look at picture:

Part 1) This image may be the result of the

we know that

The steps to construct a parallel through a point are

1) Using your straightedge, draw a transversal through point P (segment PQ)

2) Using the construction COPY AN ANGLE, construct a copy of the angle formed by the transversal and the given line such that the copy will be located UP at point P. The vertex of the copied angle will be point P.

3) When you draw the line to complete the angle copy, you will be drawing a line parallel to the given line.

therefore

The answer Part 1) is the option

B.) construction of a line parallel to line AB through point P.

Part 2) If m∠RQS is °, then m∠TPU is

we know that

m∠TPU= m∠RQS ------> by corresponding angles

so

m∠TPU=°

therefore

The answer Part 2) is the option

B.) 75

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°