What is an equation, in point slope form, for a line that passes through (4,5) and (-3,-1)?
a. y+1=67(x+3)y+1=67(x+3)

b. y+1=65(x+3)y+1=65(x+3)

c. y+3=76(x+1)y+3=76(x+1)

d. y−1=67(x−3)

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

32

step-by-step explanation: