Twice the difference of two numbers is 14 and their sum is 3

find the numbers.

They are 5 and minus 2

You have to solve the system of equations
2(a-b)=14
a+b=3

Let, x+y = 3
2(x-y) = 14

Substitute value from eq (1) in eq (2),
2(3-y-y) = 14
2(3-2y) = 14
6-4y = 14
-4y = 8
y = -2

Put it into eq (1),
x-2 = 3
x = 5

So, x = 5 & y = -2

Hope this helps!

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.