What is the result of isolating y2 in the equation below?

(x - 2)^2 + y2 = 64

a. y2 = -x2 + 4x + 60
b. y2 = -x2 + 4x + 4
c. y2 = 64 - x2
d. y2 = x2 + 4x + 60

Answer with explanation:

The given equation which represents a circle having center at, (2,0) and radius =8 is,

Result  of isolating y² in the equation below, gives

   Option A

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0