The expected number of free throws is the probability of one free throw (70%) times the number of free throws. 6 * 0.7 = 4.2 so you expect about 4 free throws out of the 6. as you can see in the simulations above, the number of scores were all close to 4.

a) Let 0-6 stand for a score and 7-9 stand for a miss. This means 7 numbers that mean score and 3 numbers that mean miss, which gives it a 70% chance. Take 6 of the digits for each of the 5 simulations. 189741- 3 scores 586463- 5 scores 856648- 4 scores 770615- 4 scores 645468- 5 scores

__tx= 60 inches. __cause it's equal to vt