Find two consecutive even integers such that the square of the first, decreased by the second is 130

Let's make the first even integer m and the second even integer n. The square of the first, decreased by the second is 130 is:

-n=130  ---> Add n to each side
=130+n ---> Take the square root of each side
m=±

Let's look at the first square number above 130, which is . m is 12, therefore the next consecutive even integer is 14.

=144
144-14=130

The two consecutive integers are 12 and 14

The answer to this question is c

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