If f(x)=integral of sqrt(t^3+1) dt from 0 to x, then f'(2)=?

F'(2) = 3

Using Fundamental Theorem of Calculus:

Since x = 2, you now have:

so F'(x) =

--> F'(2) = = = 3

so F'(2) = 3

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

it would be 6xy and -16xy.