Apipe that is 3.1 meters long is placed vertically in a pond. its lowest point is 1.5 meters under the water surface. how far above the water surface is the top of the pipe?

Answer

Find out the  how far above the water surface is the top of the pipe .

To prove

As given

A pipe that is 3.1 meters long is placed vertically in a pond.

Its lowest point is 1.5 meters under the water surface.

thus

The  top of the pipe far above the water surface = 3.1 - 1.5

                                                                                = 1.6 meter

Therefore the   top of the pipe far above the water surface is 1.6 meter .

1/5^2 = 7.56/45

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.