The bottom edge of a 16-foot long cantilever is given by the equation y = 2Vx, where y is the distance the bottom edge is from ground height, in feet.

y

(a) What is the value of b, the height of the

cantilever, in feet?

b

T

y=2&x

b) To the nearest tenth of a foot, what is the

thickness, T, of the cantilever at x =6 feet?

Step-by-step explanation:

Given

See attachment

Solving (a): Find b

At point b,

So, the value of b is:

Solving (b): Find T

First, we calculate the value of y at point T

At point T,

So:

To calculate T, we subtract the calculated height (y) from the value of b

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: it's a

step-by-step explanation: