Help me pls?

A

Step-by-step explanation:

Given

y = - x² + 6x - 1

Since the coefficient of the x² term < 0 , then graph is a maximum

The only 2 possible are A and D

Calculate the coordinates of the vertex

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

= -

y = - x² + 6x - 1 ← is in standard form

with a = - 1 and b = 6 , then

= - = 3

Substitute x = 3 into the equation for y- coordinate of vertex

y = - 3² + 6(3) - 1 = - 9 + 18 - 1 = 8

vertex = (3, 8 )

Graph A has its vertex at (3, 8 )

Then graph A best represents y = - x² + 6x - 1

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)