How do you write an equation in slope-intercept form for the line through the given points (8, 10) and (14, 13)

y=1/2x+6

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(13-10)/(14-8)

m=3/6

simplify

m=1/2

y-y1=m(x-x1)

y-10=1/2(x-8)

y=1/2x-8/2+10

y=1/2x-4+10

y=1/2x+6

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

i wish i could you, i have no idea how to answer this

step-by-step explanation: