the fastest 3 runners in a race qualify for the next event. how many different groups of Runners could advance to the next event from a race that has seven runners​

35 different groups of 3 runners can be selected

Step-by-step explanation:

Here, we want to simply calculate the number of 3 runners that can advance in a race from a total of 7

What we want to do here is to simply get different groups of 3

So, we have it that we simply want to know the number of different ways we can select 3 from a total of 7

We can simply use combination for this;

We have the general combinatorial as;

nCr = n!/(n-r)!r!

With respect to this particular question, n = 7 and r = 3

So we have;

7C3 = 7!(7-3)!3! = 7!/(4)!3! = 35

idk this answer sorry cant on this one.

step-by-step explanation:

step-by-step explanation:

the true ones are a b and d