for the following parabola:
(x - 1)^2 = 12(y + 2)
Mathematics, 19.04.2021 09:30 zaylencollins55
What is the coordinate of the focus
for the following parabola:
(x - 1)^2 = 12(y + 2)
Answers: 2
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What is the coordinate of the focus
for the following parabola:
(x - 1)^2 = 12(y + 2)
for the following parabola:
(x - 1)^2 = 12(y + 2)
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