1900 10. In the following diagram it is given that DEC, AB || DC, AD || EB and AD BC.
(a) Why isn't ABCD a parallelogram even though it has a pair of
parallel side and a pair of congruent sides?
А
2
с
E
D
(b) Explain why BE must be congruent to BC. Further explain what type of triangle this makes AEBC and
what it tells you about 1 and 22.
(C) Finally, why must 23= 21? Further, explain why we now know that 23% 22.
00
11. Given that ABCD is a parallelogram with diagonal AC bisecting ZBCD, prove
that ABCD must be a rhombus.
3
2
1
с
D
lol

what are you trying to solve here

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt