I'm really struggling to figure out the horizontal shift on this assignment. All of my other values are correct but my horizontal shift just isn't coming out right. I was assuming the horizontal shift of the cos function would be -pi/12 while the sin would be -pi/24, but when I plug these numbers into their respective functions, the horizontal shift says 1/2. Can someone just check my work? I only have 260 points but I'm willing to give all of them.

what's the question?

Step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the two may have that, even a breakdown is probably offered