GEOMETRY HELP PLEASE!! WILL MARK BRAINLEIST!
4

QX = 5.7 units

Step-by-step explanation:

Here, we want to find the value of QX

let us call this h

For a rectangle, the parallel sides have equal side lengths, and the angle at each corner is a right angle

Since X is the midpoint of SR, then XR is 1/2 * 8 = 4

So we have an isosceles right triangle in QXR, with QX as the hypotenuse since it is the side that faces the right triangle

Mathematically, for a right triangle, the square of the hypotenuse equals the sum of the squares of the two other sides

Thus;

h^2 = 4^2 + 4^2

h^2 = 16 + 16

h^2 = 32

h = √32

h = 5.7

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

2: 10

step-by-step explanation: