A box is 10 inhigh, 18 inand 12 inwide. What is the longest poster you could fit in the box?

a. 24.2 in

b. Paths of the internal diameter, where the longest poster is placed cross each other

Step-by-step explanation:

a. The longest poster that can be fitted into the box is the size of the internal diagonal of the box, that is

√((8² + 6²) +15²) = 3·√65 = 24.2 in

b. Since the above give the diagonal of the box, there can only be one poster of the dimension 24.2 in as due to path interference of the longest poster that is placed at the internal diagonal of the volume of the box

However, for the surface diagonal we have the dimension given by;

√(8² + 15²) = 23.4 in. Therefore since the side diagonal is parallel to the side of the box, one can fit several 23 in. posters which are lesser than the length of the diagonal of the side of the box side by side in the box.

Step-by-step explanation:

CarryOnLerning

MarkAsBrainliest Please

answer: get more recipes with 3 magazines for $20! i often use chicken broth instead of water. 3 tablespoons butter, divided; 1/2 cup freshly grated parmigiano-reggiano bring water and salt to a boil in a large saucepan; pour polenta slowly into 5 minutes to thicken; stir and taste for salt before transferring to a serving bowl.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.