Consider the geometric sequence below. -4, -6, -9, -2, 22,
Select all functions that define the given sequence.
Of(n) = -4.)" – 1)
f(1) = -4
f(n) = -1 . f(n − 1), for n = 2, 3, 4, ...
f(1) = 4
f(n) = - . /(n − 1), for n = 2, 3, 4, ...
f(n) = -4.(-3)'n – 1)
of(n) = 4.(-3)'n – 1)
f(1) = -4
f(n) = (n − 1), for n = 2, 3, 4, ...

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

b segment jm is correct i think