Write an equation in standard form for the line that passes through the given points. (-2, -3), (4, -7)

y = -2/3x - 13/3

Step-by-step explanation:

y=mx+b

find slope

m=(y2-y1)/(x2-x1)

(-7+3)/(4+2)

-4/6 = -2/3 = m

y-int = b = m * |x1| + y1

-2/3 * |-2| + (-3)

-4/3 - 3 = -13/3

y=-2/3x - 13/3

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

use formula for the circle a=3.14

step-by-step explanation: