What is -16t^2+80t+64=0 in factored form

=−1=−4

Step-by-step explanation:

1

Use the quadratic formula

   =−±2−4√2

t=−b±b2−4ac2at=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}t=2a−b±b2−4ac

   ​​

   Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

   162+80+64=0

   16t2+80t+64=016t^{2}+80t+64=016t2+80t+64=0

   =16

   a=16a={\color{#c92786}{16}}a=16

   =80

   b=80b={\color{#e8710a}{80}}b=80

   =64

   c=64c={\color{#129eaf}{64}}c=64

=−80±802−4⋅16⋅64√2⋅16

t=−80±802−4⋅16⋅642⋅16t=\frac{-{\color{#e8710a}{80}} \pm \sqrt{{\color{#e8710a}{80}}^{2}-4 \cdot {\color{#c92786}{16}} \cdot {\color{#129eaf}{64{2 \cdot {\color{#c92786}{16}}}t=2⋅16−80±802−4⋅16⋅64

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2

Simplify

3

Separate the equations

4

Solve

Solution

=−1=−4

the correct answer is 1.7

zero

step-by-step explanation:

f(2)= x-2

plug in the 2 in the "x"

f(2)=2-2

f(2)=0