Plz 30 points im desperate A show pony weighs at least 900 pounds. After a recent weigh in, the owner of a show pony amended the diet of his pony, increasing the animal's caloric intake, with the hope that the pony would gain weight to be shown in a few months. The data shown in the table and scatter plot below represents the pony's additional daily caloric intake and recorded weight gain (in pounds) of the show pony over the last ten weeks.
Additional Daily Calories Consumed Weight Gained

(in pounds)
1,500 3
1,575 7
1,650 3
1,725 4
1,800 8
1,875 9
1,950 13
2,025 7
2,100 17
2,175 15
Part A: Use the data shown in the table and scatter plot to create an approximate equation for the line of best fit.

Part B: In complete sentences, describe the show pony's weight gain in terms of the units used in the data.

Part C: According to the equation for the best fit line for the data, approximately how much weight would you expect the pony to gain in a week if its additional daily caloric intake for that week is 2,300 calories?

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step-by-step explanation:

it works trust me

87%

step-by-step explanation:

apex answer

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt