Find the value of the expression 2x0+x1/3 x=125

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      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen

$205,000 here you go i had to guess it but i got it correct so yeah