Mathematics, 05.02.2020 03:58 star3554
Find the coordinates of the point in the first quadrant at which the tangent line to the curve (x)^3-xy+(y)^3 =0 is parallel to the x axis.
Answers: 3
![x^3-3x^3+27x^6=0 \\ \\x^3(27x^3-2)=0\implies x=\{0,{\sqrt[3]2\over3}\}](/tpl/images/0502/6552/0b54c.png)
![(0,0)\text{ and }({\sqrt[3]2\over3},{\sqrt[3]4\over3})](/tpl/images/0502/6552/ea586.png)
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Find the coordinates of the point in the first quadrant at which the tangent line to the curve (x)^3...
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