The angle a is such that
seca + tana = 2
show that
seca-tana=1/2
hence, find the exact value of cosa.

1 / cos A + sin A / cos A = 2
( 1 + sin A ) / cos A = 2
1 + sin A = 2 cos A
sin A = 2 cos A - 1
sin² A + cos² A = 1
( 2 cos A - 1 )² + cos² A = 1
4 cos² A - 4 cos A + 1 + cos² A = 1
5 cos² A - 4 cos A = 0
cos A ( 5 cos A - 4 ) = 0,     cos A ≠ 0
5 cos A - 4 = 0
cos A = 4 / 5
sec A - tan A = 5 / 4 - 3 / 4 = 2 / 4 = 1 / 2 ( correct )

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