Gravity on the moon is much weaker than on earth. the expression below can be used to approximate the time in seconds it takes for an object to reach the surface of the moon, when dropped from a height of h meters. to the nearest hundredth of a second, how long would it take for an object dropped from a height of 50 meters to land on the moon? (enter only the number, such as 3.25 without units.) √h/0.82

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

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step-by-step explanation:

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