Suppose you launch a model rocket with an upward starting velocity of v ft/s. You can use the equation fs = –16t+ vt + hop to find the rocket's altitude, h represents height in feet, t seconds after launch and to represents initial height. Suppose the upward starting velocity is 315 ft/s and the initial height is 3 ft. When will the rocket hit the ground? ​

.5 lb

step-by-step explanation:

12 in / 6 in =2 in

.25 x 2 = .5 lb

a

step-by-step explanation:

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answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368