Adam jogs at an average speed of 10km/h from his house to the airport. The airport is 7km away from his house. At what time must Adam leave his house in order for him to reach the airport at 7:20 am.

6:38am

Step-by-step explanation:

From the question we are told that

Average speed

Distance traveled

Generally the velocity across a distance is mathematically given given as

Therefore

7:20-42 minutes =6:38am

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation: