Can someone please help me with this math problem? Please. Simplify the expression:(2x-3y)^2/(3y-2x)^2 Ava simplified the expression and said that the value is -1. (2x-3y)^2/(3y-2x)^2 (2x-3y)^2/-(2x-3y)^2 and then she has both of them crossed out (2x-3y)^2/-1(2x=3y)^2 =-1 Is Ava's solution correct? If not, find and explain her mistake. Give the correct solution.

Ava is incorrect

Step-by-step explanation:

Given

Required

Determine if Ava is correct or not

Ava's solution is incorrect and the proof is as follows;

Apply the following law of indices;

Rewrite the numerator

Cross out the common factor of the numerator and denominator

Hence, the solution is 1; not -1

Her mistake is that, she did not apply the square on -1, after she factorize the denominator

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.