Plz fast solve it and It should be right ​

9514 1404 393

  (i) ∠CDF = 86°

  (ii) ∠BAD = 141°

Step-by-step explanation:

(i) Angles CDF and GFD are "alternate interior" angles, so are congruent.

  ∠CDF = 86°

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(ii) Angles BAD and CDA are "alternate interior angles, so are congruent. Angle CDA is the sum of angles CDH and HDA. Angle CDH is supplementary to angle CDF, so is ...

  ∠CDH = 180° -∠CDF = 180° -86° = 94°

Then ...

  ∠CDA = ∠CDH +∠HDA = 94° +47°

  ∠CDA = 141°

each side has a different length.  

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐