an astronaut drops a rock off the edge of a cliff on the moon. the distance, d(t), in meters, the rock travels after t seconds can be modeled by the function d(t) = 0.8t^2. what is the average speed, in meters per second, of the rock between 5 & 10 seconds after it was dropped?

The average speed between the times given is 12 m/s

Step-by-step explanation:

Here, we want to calculate rate of change between the times given

Mathematically , we can get the average rate of change using the formula

f(b)-f(a)/b-a

in this case, b = 10 s and a = 5 s

f(b) is d(10) = 0.8(10)^2 = 80

f(a) is d(5) = 0.8(5)^2 = 20

Rate of change is thus;

(80-20)/(10-5) = 60/5 = 12 m/s

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12