Solve: 1/3(−6q+4)=−1/12(4q+4)

Combine multiplied terms into a single fraction

13(−6+4)=−112(4+4)

13(−6q+4)=−112(4q+4)\frac{1}{3}(-6q+4)=\frac{-1}{12}(4q+4)31​(−6q+4)=12−1​(4q+4)

1(−6+4)3=−112(4+4)

1(−6q+4)3=−112(4q+4)\frac{1(-6q+4)}{3}=\frac{-1}{12}(4q+4)31(−6q+4)​=12−1​(4q+4)

2

Multiply by 1

3

Combine multiplied terms into a single fraction

4

Distribute

5

Multiply all terms by the same value to eliminate fraction denominators

6

Cancel multiplied terms that are in the denominator

7

Distribute

8

Subtract

16

161616

from both sides of the equation

9

Simplify

10

Add

4

4q4q4q

to both sides of the equation

11

Simplify

12

Divide both sides of the equation by the same term

13

Simplify

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Solution

=1

Step-by-step explanation:

q=1

Step 1: Simplify both sides of the equation.

Step 2: Add 1/3q to both sides.

Step 3: Subtract 4/3 from both sides.

Step 4: Multiply both sides by 3/(-5).

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

a

step-by-step explanation: