Determine if the side lengths listed create a right triangle, acute triangle, obtuse triangle, or do not make a triangle. 3, 9, 10 Determina si las longitudes de los lados enumeradas crean un triángulo rectángulo, un triángulo agudo, un triángulo obtuso o no forman un triángulo. 3, 9, 10 * 1 point right acute obtuse not a triangle

Obtuse triangle

Step-by-step explanation:

Given the side lengths :

3, 9, 10

Let :

a = 3 ; b = 9 ; c = 10 (longest side)

If a² + b² = c² (right angle)

If a² + b² > c² (acute angle)

If a² + b² < c² (obtuse angle)

a² + b²

3² + 9²

9 + 81 = 90

c² = 10² = 100

90 < 100

Hence,

a² + b² < c² (then we have an obtuse triangle)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

5

step-by-step explanation: