In a random sample of 8 residents of the state of Montana, the mean waste recycled per person per day was 3.0 pounds with a standard deviation of 0.23 pounds. Determine the 99% confidence interval for the mean waste recycled per person per day for the population of Montana. Assume the population is approximately normal. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

at 99%, Confidence interval is ( 2.716, 3.285 )

( 2.716 < μ < 3.285 )

Step-by-step explanation:

Given the data in the question;

sample size n = 8

mean x' = 3.0

standard deviation σ = 0.23

To calculate the confidence interval, we use the following expression;

x' ± ( σ/√n) ------- let this be equation

now, at 99% confidence interval;

∝ = 1 - 99% = 1 - 0.99 = 0.01

degree of freedom df = n - 1 = 8 - 1 = 7

hence t-critical value = 3.499

in equation 1, we substitute in our values;

⇒ 3.0 ± 3.499( 0.23/√8  )

⇒ 3.0 ± 0.2845

⇒ 3.0 - 0.2845, 3.0 + 0.2845

⇒ ( 2.7155, 3.2845 )

Therefore at 99%, Confidence interval is ( 2.716, 3.285 )

( 2.716 < μ < 3.285 )

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90