Give the starting value a, the growth factor b, and the growth rate r if q = abt = a(1 + r)t . write r as a percent. q=79(1.002)^t

r as a percent will be equal to 0.2%.

Step-by-step explanation:

It is given that Q = =    ........... (1)

Also,      Q =       .......... (2)

Thus, equating both equations (1) and (2), we will get the equation as follows.

            =       ........ (3)

Therefore, from equation (3) we can conclude that the value of a = 79 and (1 + r) = 1.002

Since,                1 + r = 1.002

thus,                      r = 1.002 - 1

                             r = 0.002

Now, convert 0.002 into fraction form as follows.

Therefore, r as a percent will be as follows.

                      × 100%

Hence, r as a percent will be equal to 0.2%.

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn