Find the perimeter of these figures *
please*

The perimeter of figure a is 44 inches, the perimeter of figure b is 72 inches.

Step-by-step explanation:

The sides of figure a is 8; 2; 3; 12; 2; 12; 3; 2, to get the perimeter, add all the sides together, which will be 8 + 2 * 2 + 3 * 2 + 12 * 2 = 8 + 4 + 6 + 24 = 12 + 30 = 42 inches. The sides of figure b is 3; 3; 3; 3; 13; 13; 5; 5; 5; 5; 7; 7, to get the perimeter, add all the sides together, which will be 3 * 4 + 13 * 2 + 5 * 4 + 7 * 2 = 12 + 26 + 20 + 14 = 32 + 40 = 72 inches.

a) 44

2 + 8 + 2 + 8 + 12 + 12 = 44

b) 72

13 + 13 + 3 +3 +3 +3 +5 +5 +5 +5 +7 +7 = 72

Step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet