the times for the mile run of a large group of male college students are approximately normal with mean 7.11 minutes and standard deviation 0.74 minutes.
use the 68–95–99.7 rule to answer the following questions.
(start by making a sketch like figure 3.8.)

1. what range of times covers almost all (99.7%) of this distribution?
a. 5.63 to 8.59
b. 4.89 to 9.33
c. 6.37 to 7.85
d. 2.22 to 12

The rule is that for normally distributed data:

- 68% are in the range mean +/-  1*standard deviation
- 95% are in the range mean +/-  2*standard deviation
- 99.7% are in the range mean +/-  3*standard deviation

Then in this case the range is from 7.11 minutes - 3*0.74 minutes to 7.11 minutes + 3*0.74 minutes

This is, 7.11 -  2.22 to 7.11 + 2.22

Equal to 4.89 to 9.33

Then, the answer is the option B.