A cylinder has a radius of 4 inches and a height of 5 inches. If the radius of the cylinder is tripled and the height remains the same to create a new cylinder, what will be the difference in the surface areas of the two cylinders? Answer in terms of Pi.

A cylinder has a radius of 4 inches and a height of 5 inches. If the radius of the cylinder is tripled and the height remains the same to create a new cylinder, what will be the difference in the surface areas of the two cylinders ? Answer in terms of Pi.

A cylinder has a radius of 4 inches and a height of 5 inches.

If the radius of the cylinder is tripled and the height remains the same to create a new cylinder, what will be the difference in the surface areas of the two cylinders ?

Radius is 4 inches

Height is 5 inches

Radius is 3 × 4 = 12 inches [as in the question it is given that the radius of the cylinder is tripled]

Height is 5 inches

Now,

Surface area of 1st cylinder

is 2πr(r + h) = 2π × 4(4 + 5)

= 8π(9)

Surface area of 2nd cylinder

is 2πr(r + h) = 2π × 12(12 + 5)

= 24π(17)

The difference in the surface areas of the two cylinders is = = (408π - 72π) = 336π sq inches

(4,5

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