The circumference of the base of a 5
-foot-high cylinder is
46
inches. What is the volume of the cylinder?

V≈33238.05

Step-by-step explanation:

The circumference of the cylinder base is

= ( 2 )*(pi)*( r ) cm where r = radius of the circular base.

That is ( 2 )(pi)( r ) = ( 44 )cm or

( radius ) = [ (44/((2)(pi)) ] = ( 7.0064 )cm.

I have approximated ( pi ) as ( 3.14 ) for this calculation.

The area of the cylindrical base is ( pi )*( radius )^2

Therefore area of the base

= ( 3.14 )*( 7.0064 )^2 =( 154.1415 )cm squared.

Volume of Cylinder

Volume = Atea of the base multiplied by cylinder height or

= ( 154.1415 ) * ( 7 )

= ( 1079.0 ) cubic centimeters approximately with some slight loss inaccuracy due to rounding of pi.

Lateral Surface Area

The lateral surface area = circumference of the cylindrical base multiplied by the height of the cylinder.

= ( 44 )*( 7 ) = ( 308 ) cm squared

Inherent Assumption

It is assumed that the thickness of the cylinder material is small and the cylinder doesn't overlap the area of the base. If it did, the lateral surface area calculated here might be understated slightly.

yo

step-by-step explanation:

yo

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2