Suppose is an angle in the standard position whose terminal side is in Quadrant IV and cot =- values of the five remaining trigonometric functions of 0.
// 름
Find the exact
sin -
cos e
17
293
csc
293
2
sec -
293
17
17
tan -
2
293
2
sin e
17
293
COS
CSC -
293
17
sec e
/293
2
tan
1293
17
2
sin e
17
293
cos -
2
293
1293
CSC -
2
sec en
293
17
17
tan -
1293
2
293
17
sin e
cos O.-
csc e-
17
V293
sec
2
tan -
17
2
1293

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

square pyramid

step-by-step explanation:

square prism looks like nothing like that

triangular prism has a rectangular base instead of a square base

tetrahedron has a triangular base