Two sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º. Find the area of the parallelogram to the nearest square
foot.

Step-by-step explanation:

Given that,

The sides of a parallelogram are 49 feet and 78 feet. The measure of the angle  between these sides is 59º.

We need to find the area of the parallelogram.

Using trigonometry,

We know that,

Area = base (b) × height (h)

So,

So, the area of the parallelogram is equal to .

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)