HELP ASAP

if dy/dx = 2 - y, and if y = 1 when x = 1, then y = ??? PHOTO ATTACHED

y=2-e^(1-x)

Step-by-step explanation:

This can be solved by separating the variables.

dy/dx=2-y

Multiply both sides by dx

Divide 2-y on both sides

dy/(2-y)=dx

Integrate both sides

-ln|2-y|=x+c

Multiply both sides by -1

ln|2-y|=-x-c

Equivalent logarithm form

2-y=e^(-x-c)

Minus 2 on both sides

-y=e^(-x-c)-2

Multiply both sides by -1

y=-e^(-x-c)+2

The ordered pair (1,1) belongs to the curve so we have

(I'm going to use this earlier form -ln|2-y|=x+c)

-ln|2-1|=1+c

-ln|1|=1+c

-0=1+c

0=1+c

Minus 1 on both sides

-1=c

y=-e^(-x-(-1))+2

Or

y=-e^(-x+1)+2

Or

y=2-e^(1-x)

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

step-by-step explanation: