Suppose that Uranus rotates on its axis once every 17.2 hours. The equator lies on a circle with a radius of 15,881 miles. (a) Find the angular speed of a point on its equator in radians per day (24 hours). (b) Find the linear speed of a point on the equator in miles per day. Do not round any intermediate computations, and round your answer to the nearest whole number. (a) Angular speed: radians per day (b) Linear speed : miles per day

a) 2π radians /day

b) 31,762π miles / day

Step-by-step explanation:

I will have to ASSUME that by "day" we mean a Uranus day which just happens to be only 17.2 earth hours long.

one revolution is 2π radians, so angular speed anywhere, not just the equator, is 2π radians /day

Miles about the equator will equal the circumference of a circle with formula

C = 2πR

C = 2π15881 = 31862π miles or about 99,783 miles

If we want the answers in Earth days, we need to multiply each answer by a factor of  24 / 17.2

Please select Brainliest if it fits.

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane