Find the equation of a line that is perpendicular to 4x+6y=1 and that has a greater intercept to the line 2x+3y=18

2y - 3x = -15

Step-by-step explanation:

Slope of the line 4x + 6y = 1 is as shown below;

Rewrite in slope intercept form;

6y = -4x+1

y = -4x/6 + 1/6

y = -2x/3 + 1/6

mx = -2/3x

m = -2/3

The slope of the line perpendicular M = -1/(-2/3)

M = 3/2

Get the x and y intercept of 2x+3y = 18

x intercept occurs when y  = 0

2x + 0 = 18

x= 18/2

x = 9

y intercept occurs when x  = 0

0 + 3y = 18

3y= 18

y = 18/3

y = 6

The line passes through the point (9,6)

Write the equation in point slope form

y - y0 = m(x-x0)

y - 6  = 3/2(x-9)

2(y-6) = 3(x-9)

2y - 12 = 3x - 27

2y - 3x = -27 + 12

2y - 3x = -15

This gives the required equation