Mathematics, 10.04.2021 01:00 ashley352

What is the angle relationship?

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Mathematics, 21.06.2019 14:50, tinasidell1972

Need to increase the numbers of customers i talk to daily by 20% how many customers do i need to talk to if i talk to a average of 8 customers per hour during an 8 hour shift

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Mathematics, 21.06.2019 19:40, sswd

The owners of four companies competing for a contract are shown in the table below. if a report is released that advocates company b, which of the people having funded the report should result in the most skepticism? company owner of company company a jake adams company b company c company d debby smith henry rose rhonda baker o a. jake adams o b. rhonda baker o c. debby smith o d. henry rose

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Mathematics, 22.06.2019 00:00, rmans22209

Urgent! 20 points! here is a you are the new manager at trusty goods wholesale produce. you need to figure out how to adjust the amount of produce in your notes after the events of the day: you got 5 more crates of bananas someone returned 2 crates of apples a worker dropped a crate of grapes (oh no! , you had to throw them out) you sold a crate of bananas you sold 5 crates of apples can you write an expression to describe your day using: "a" for crates of apples "b" for crates of bananas and "g" for crates of grapes? make sure the expression is in simplest form question 2 (3 points) explain your steps using sentences.

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Mathematics, 22.06.2019 01:00, SpeechlessZzz9920

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)