Find the Median, the lower quartile, the upper quartile, and the interquartile range of each data set. 1. Ages, in years, of the 12 children at the playground: 5, 8, 6, 11, 5, 4, 7, 3, 5, 9, 6, and 8.
Median:? Lower Quartile:? Upper quartile:? Interqurtile Range:?

2. Hight, in feet, 14 lemon trees: 12.4, 11.8, 14.6, 13, 11.2, 15, 13.4, 11, 12.8, 13, 11.2, 14.4, 12 and 13.2
Median:? Lower Quartile:? Upper Quartile:? Interquartile Range:?

3. Scores of nine football players in a season: 33, 42, 31, 27, 47, 23, 40, 45, and 43
Median... Interquartile Range

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

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step-by-step explanation: