1. Determine the lateral and total surface area of the pyramid.

(I need full explanation on how to solve

Laterial surface area: 73 cm²Total surface area: 93 cm²

Step-by-step explanation:

The laterial surface area is the sum of the areas of the triangles. There are two triangles with dimensions: base = 4 cm, height = 8cm and two triangles with dimensions: base = 5cm, height = 8.2cm.

The laterial surface area LSA is:

LSA = 2 • ( 4.8/2) + 2 • ( 5 • 8.2/2)

LSA = 4 • 8 + 5 • 8.2

LSA = 73 cm²

The total surface area SA is the LSA plus the area of the base of the pyramid, which is a rectangle with dimensions: 4cm x 5cm:

SA = LSA + 4 • 5

SA = 73 cm + 20 cm²

SA = 93 cm²

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12